Q31: Which of the following statement is not correct for the principle of surveying?
  • Location of a point with respect to two references
  • Major control points are measured with higher degree of precision
  • Minor control points are measured with lower degree of precision
  • Working from part to whole

Correct Answer: D. Working from part to whole

Solution:

The fundamental principle is "working from the whole to the part" to prevent the accumulation of errors. Working from part to whole is incorrect and would magnify errors throughout the survey. The other statements are correct applications or principles of surveying.

Q32: Which one of the following set of internal angles (degree) of a triangle does show a well-conditioned triangle?
  • 20, 90, 70
  • 25, 45, 110
  • 40, 125, 15
  • 35, 80, 65

Correct Answer: D. 35, 80, 65

Solution:

A well-conditioned triangle is one where no angle is too small (less than 30°) or too large (greater than 120°). This ensures a sharp and accurate intersection when plotting. In option D, all angles (35°, 80°, 65°) are within the ideal range. The other options contain angles that are either too acute or too obtuse, making them ill-conditioned.

Q33: Determine the number of divisions required on the vernier scale, if it is combined with the main scale of least count 0.5 mm. The least count of the combination required is 0.05 mm for the direct vernier.
  • 0.025
  • 0.1
  • 1
  • 10

Correct Answer: D. 10

Solution:

For a direct vernier, the least count (LC) is the difference between one smallest division on the main scale (s) and one smallest division on the vernier scale (v). The relationship is given by the formula: LC = s / n, where 'n' is the number of divisions on the vernier scale.
Given: s = 0.5 mm, LC = 0.05 mm.
n = s / LC = 0.5 / 0.05 = 10.
Therefore, 10 divisions are required on the vernier scale.

Q34: A surveyor measures a distance between two points on a map of representative fraction of 1:100 is 60 m. But later he found that he used a wrong representative fraction of 1:50. What is the correct distance between the two points?
  • 30
  • 45
  • 90
  • 120

Correct Answer: D. 120 m

Solution:

This problem implies the surveyor calculated a ground distance of 60 m by measuring a distance on the map and incorrectly using an RF of 1:50. The map's actual RF is 1:100.
1. First, find the distance on the map:
Calculated Distance = Map Distance / Wrong RF => 60 m = Map Distance / (1/50).
Map Distance = 60 / 50 = 1.2 m.
2. Now, use the correct RF to find the true ground distance:
Correct Distance = Map Distance / Correct RF = 1.2 m / (1/100) = 1.2 * 100 = 120 m.

Q35: Which one is the upper limit of survey area (square kilometer) for use of plane survey?
  • 250
  • 300
  • 350
  • 450

Correct Answer: A. 250

Solution:

In plane surveying, the Earth's curvature is not taken into account. This is a valid assumption for small areas. The generally accepted upper limit for treating a survey as 'plane' is about 250 square kilometers. For areas larger than this, geodetic surveying, which accounts for the Earth's spheroidal shape, is necessary to maintain accuracy.

Q36: Which one is the smallest scale?
  • 1 : 100
  • 1 : 500
  • 1 : 1000
  • 1 : 2,500

Correct Answer: D. 1 : 2,500

Solution:

A map scale is a ratio of map distance to ground distance. A "smaller" scale means the ratio is smaller. For example, 1:2,500 is equivalent to the fraction 1/2500, while 1:100 is 1/100. Since 1/2500 is a smaller number than 1/100, 1:2,500 is the smallest scale. Small-scale maps cover large areas with less detail.

Q37: Which of the following statement is CORRECT for estimating the corrected area from a map of shrunk factor 'F'?
  • It is directly proportional to F
  • It is directly proportional to square of F
  • It is inversely proportional to F
  • It is inversely proportional to square of F

Correct Answer: D. It is inversely proportional to square of F

Solution:

The relationship for corrected area based on a shrunk map is: Correct Area = Measured Area / (Shrunk Factor)². Therefore, the corrected area is inversely proportional to the square of F.

Q38: Which one of the following is the largest scale?
  • 1 : 500
  • 1 : 1000
  • 1 : 2500
  • 1 : 50,000

Correct Answer: A. 1 : 500

Solution:

A "larger" scale has a smaller denominator. The ratio 1/500 is a larger number than 1/1000 or 1/50000. Large-scale maps show more detail for a smaller area.

Q39: The curvature of the earth's surface is taken into account if the extent of survey is more than:
  • 100 km²
  • 160 km²
  • 500 km²
  • 260 km²

Correct Answer: D. 260 km²

Solution:

For surveys covering an area greater than approximately 250-260 km², the curvature of the Earth becomes significant and must be accounted for to maintain accuracy. This type of survey is known as geodetic surveying.

Q40: The type of surveying in which the curvature of the earth is taken into account is called ........
  • Geodetic surveying
  • Plane surveying
  • Preliminary surveying
  • Topographical surveying

Correct Answer: A. Geodetic surveying

Solution:

Geodetic surveying is the method used for large areas where the Earth's spherical shape is considered. In contrast, plane surveying assumes the Earth is flat and is only suitable for smaller areas.

Q41: In case of a direct vernier scale .........
  • graduations increase in the opposite direction in which graduations of the main scale increase
  • the smallest division is longer than the smallest division of the main scale
  • graduations increase in the same direction in which graduations of the main scale increase
  • None of these

Correct Answer: C. graduations increase in the same direction in which graduations of the main scale increase

Solution:

A direct vernier scale is constructed so that its divisions are slightly smaller than the main scale divisions, and they are marked in the same direction. This is the most common type of vernier scale.

Q42: Difference in length of an arc and its subtended chord on the earth's surface for a distance of 18.2km is _______.
  • 10 mm
  • 15 mm
  • 22 mm
  • 100 mm

Correct Answer: A. 10 mm

Solution:

The difference between the length of a long arc and its corresponding chord on the Earth's surface is approximately 1 cm (10 mm) for every 18.2 km of length. This is a standard value used in geodetic calculations to account for the Earth's curvature.

Q43: Geodetic survey is different from plane surveying because of ________.
  • Very large area is covered
  • The curvature of the earth is considered
  • Undulations of the topography
  • The large difference of elevations

Correct Answer: B. The curvature of the earth is considered

Solution:

The fundamental distinction between plane and geodetic surveying is the treatment of the Earth's shape. Plane surveying assumes a flat surface, while geodetic surveying accounts for its curvature. While large areas often necessitate geodetic methods, the consideration of curvature is the defining technical difference.

Q44: In a diagonal scale only _______.
  • Units can be shown
  • Units, tenths can be shown
  • Units, tenths and hundredths can be shown
  • Units, tenths, hundredths and thousandths can be shown

Correct Answer: C. Units, tenths and hundredths can be shown

Solution:

A diagonal scale is a graphical tool used for precise measurements. By using the principle of similar triangles, it can represent three different units or a main unit and its two subdivisions (e.g., meters, decimeters, and centimeters). This allows for reading units, tenths, and hundredths of a unit.

Q45: When 1 cm on a map represents 10 m on the ground, the representative fraction of the scale is:
  • 1 / 100
  • 1 / 1,000
  • 1 / 10,000
  • 1 / 10

Correct Answer: B. 1 / 1,000

Solution:

To calculate the Representative Fraction (RF), the units must be the same.
First, convert 10 meters to centimeters: 10 m * 100 cm/m = 1,000 cm.
The scale is 1 cm on the map to 1,000 cm on the ground.
Therefore, the RF is 1 / 1,000.