Problem Statement
A block of wood floats in water and glycerin under the following conditions:
- Projection above water surface: 40 mm
- Projection above glycerin surface: 70 mm
- Specific gravity of glycerin: 1.35
Determine the specific gravity of the wooden block.
Solution
1. Define Equilibrium Conditions
2. Equating Weight in Water
3. Equating Weight in Glycerin
4. Calculate Specific Gravity of Wood
- Specific gravity of the wooden block: 0.74
Explanation
1. Floating Equilibrium:
A floating object displaces a volume of liquid equal to its own weight. Since the wooden block is floating, the weight of the wood is equal to the weight of the displaced liquid.
2. Use of Two Liquids:
The block projects differently in water and glycerin due to their different densities. Since glycerin is denser than water, the block displaces less glycerin than water to maintain equilibrium.
3. Calculation of Specific Gravity:
The height of the block is unknown, so we first set up equilibrium conditions in both water and glycerin. By solving for the total height \( h \) and using it in the specific gravity equation, we determine \( S \).
4. Verification:
The final value \( S = 0.74 \) is reasonable for a wooden block, confirming that the solution is accurate.
Physical Meaning
1. Role of Specific Gravity in Floating Objects:
The specific gravity of an object determines how much of it will be submerged in a liquid. If \( S < 1 \), the object floats; if \( S > 1 \), it sinks.
2. Application in Shipbuilding:
Engineers use this principle when designing ships to ensure they float with the desired portion above the water level.
3. Industrial Applications:
In industries, materials are selected based on their specific gravity to ensure they float or sink as needed in various processes.




