Q16: The length of a line measured by a 30 m chain was found to be 450 m. If the chain was 0.2 links short, then find the true length of the line:
  • 448.0 m
  • 449.1 m
  • 449.8 m
  • 449.4 m

Correct Answer: D. 449.4 m

Solution:

A standard 30 m chain has 150 links (1 link = 0.2 m).
The chain is short by 0.2 links. Error in length = 0.2 links × 0.2 m/link = 0.04 m.
Actual length of chain (L') = 30 m - 0.04 m = 29.96 m.
Designated length of chain (L) = 30 m.
Measured length = 450 m.
True Length = (L'/L) × Measured Length = (29.96 / 30) × 450 = 449.4 m.

Q17: Select the INCORRECT obstacle in chaining in a chain survey:
  • Obstacle to ranging only
  • Obstacle to chaining only
  • Obstacle to plotting
  • Obstacle to both chaining and ranging

Correct Answer: C. Obstacle to plotting

Solution:

Obstacles in chain surveying are physical obstructions in the field that affect the process of measuring (chaining) or seeing (ranging). Plotting is the process of drawing the survey on paper, which is done after the fieldwork is complete. Therefore, an "obstacle to plotting" is not a field obstacle encountered during chaining.

Q18: Among the following corrections applied for tape measurement, identify the correction which is NOT always negative in sign:
  • Sag
  • Slope of tape
  • Pull
  • Wrong alignment

Correct Answer: C. Pull

Solution:

Corrections for sag, slope, and wrong alignment are always negative because they result in a measured length that is longer than the true length. The pull (or tension) correction can be positive, negative, or zero. It is positive if the pull applied is greater than the standard pull, and negative if it is less.

Q19: The correction due to wrong alignment of the tape:
  • is always negative
  • can be positive or negative
  • depends upon whether the alignment is wrong to the right or left of the line
  • is always positive

Correct Answer: A. is always negative

Solution:

When a tape is not aligned in a straight line between two points, the measured distance will always be greater than the true straight-line distance. Therefore, the correction to get the true distance must always be negative (subtracted from the measured distance).

Q20: ........... is 33 feet long and is mostly used for cadastral surveying.
  • Band chain
  • Gunter's chain
  • Revenue chain
  • Metric chain

Correct Answer: C. Revenue chain

Solution:

The Revenue chain is 33 feet long and divided into 16 links. It was historically used in India for cadastral surveys, which are surveys of property boundaries, especially for land registration and taxation purposes. Gunter's chain is 66 feet long.

Q21: Offsets are of two types _______
  • Horizontal and vertical
  • Horizontal and curved oblique
  • Perpendicular and oblique
  • Straight and oblique

Correct Answer: C. Perpendicular and oblique

Solution:

Offsets are lateral measurements taken from a survey line to locate points or features. They are classified based on their angle to the survey line: Perpendicular (at 90°) and Oblique (at any other angle).

Q22: Which one is the CORRECT option for the cumulative errors?
1. It decreases with an increase in measurement.
2. It is directly proportional to the length of the line.
3. It may be positive or negative.
4. It is inversely proportional to the length of the line.
  • 1, 3 and 4
  • 1 and 3
  • 2 and 3
  • Only 2

Correct Answer: C. 2 and 3

Solution:

Cumulative errors build up in the same direction. Their magnitude is generally proportional to the length of the line being measured (Statement 2), and they can be either positive (making the measurement too long) or negative (making it too short) (Statement 3).

Q23: Which of the following is a reason for negative error in chaining?
  • Rise in temperature
  • Sag in chain
  • Chain getting out of line due to wrong ranging
  • Chain not being straight

Correct Answer: A. Rise in temperature

Solution:

Error = Measured Value - True Value. A rise in temperature causes the chain to expand, making it longer than its standard length. A longer chain under-measures the true distance (the measured value is less than the true value), resulting in a negative error. Sag and misalignment always cause positive errors (measured value > true value).

Q24: Calculate the limiting length (m) of the offset, if the maximum allowable error in laying the offset is 2 degrees. The scale of the map is 1 cm = 100 m.
  • 2.5
  • 71.63
  • 250
  • 2865

Correct Answer: B. 71.63

Solution:

The maximum permissible error on drawing paper is typically taken as 0.25 mm or 0.025 cm.
Maximum error on ground = 0.025 cm × (100 m / 1 cm) = 2.5 m.
The error in length due to an angular error is given by e = L sin(θ).
So, L = e / sin(θ) = 2.5 m / sin(2°) ≈ 71.63 m.

Q25: Which of the following instruments is used for setting out right angles?
  • Clinometers
  • Offset rod
  • Prism square
  • Plumb bob

Correct Answer: C. Prism square

Solution:

A prism square is an optical instrument specifically designed for accurately and quickly setting out right angles (90°) to a survey line. A clinometer measures vertical angles, an offset rod measures short distances, and a plumb bob establishes a vertical line from a point.

Q26: Determine the normal pull (kg) for a tape of 20 m long standardized at a pull of 30 kg. The cross-section area of the tape is 0.5 square centimetres, and the weight of the tape per metre is 20 gm. Take the modulus of elasticity for the tape material as 2,100,000 kg per square centimetre.
  • 28
  • 36.8
  • 64
  • 78

Correct Answer: B. 36.8 kg

Solution:

Normal pull is the pull at which the correction for pull and the correction for sag cancel each other out.
Let Pn be the normal pull. Total weight of tape (W) = 20 gm/m * 20 m = 400 gm = 0.4 kg.
Pull Correction = (Pn - P_standard) * L / (A * E)
Sag Correction = -W² * L / (24 * Pn²)
Setting them equal: (Pn - 30) * 20 / (0.5 * 2100000) = (0.4)² * 20 / (24 * Pn²)
Simplifying gives a cubic equation for Pn. Solving it yields Pn ≈ 36.8 kg.

Q27: The number of links in a 20 m metric chain is ............
  • 80
  • 100
  • 120
  • 150

Correct Answer: B. 100

Solution:

In a standard metric chain, each link is 20 cm (0.2 m) long. Therefore, a 20-metre chain has 20 m / 0.2 m/link = 100 links.

Q28: The hypotenuse allowance (in m) for a 30 m long chain, if the slope is 1:10 is ..........
  • 0.1
  • 0.12
  • 0.15
  • 0.22

Correct Answer: C. 0.15

Solution:

A slope of 1:10 means for every 10 units horizontal, there is 1 unit vertical. The slope angle θ = tan⁻¹(1/10).
The required horizontal distance (true length) is Lcos(θ).
The measured slope distance is L.
Hypotenusal allowance = L(sec(θ) - 1).
For small angles, this can be approximated as L * h²/ (2L²) = h²/(2L) = (3)² / (2*30) = 0.15 m. (Using h=3 for L=30 at 1:10 slope)

Q29: Which one is the CORRECT statement?
  • Length of engineering chain is 33 ft.
  • Length of engineering chain is 66 ft.
  • Length of Gunter's chain is 66 ft.
  • Length of revenue chain is 66 ft.

Correct Answer: C. Length of Gunter's chain is 66 ft.

Solution:

Standard lengths of survey chains are:
- Gunter's Chain: 66 ft (100 links)
- Engineer's Chain: 100 ft (100 links)
- Revenue Chain: 33 ft (16 links)

Q30: The length of the chain is equal to .........
  • Centre to centre distance between the last end of links
  • Sum of reduced level of benchmark and foresight
  • Sum of reduced level of benchmark and backsight
  • Sum of reduced level of benchmark and intermediate sight

Correct Answer: A. Centre to centre distance between the last end of links

Solution:

The specified length of a survey chain is measured from the outside of the handle at one end to the outside of the handle at the other. This corresponds to the center-to-center distance between the first and last links. The other options relate to levelling, not distance measurement with a chain.