Q16: If the magnetic bearing of the Sun at a certain place in the Southern Hemisphere during noon is 336° 29', then the magnetic declination at that place is __________.
- 66° 29' W
- 66° 29' E
- 23° 31' E
- 23° 31' W
Correct Answer: C. 23° 31' E
Solution:
In the Southern Hemisphere, the Sun is exactly at the geographic north at noon. Therefore, the true bearing of the sun is 0° or 360°. The magnetic bearing is given as 336° 29'. Magnetic Declination = True Bearing - Magnetic Bearing = 360° - 336° 29' = 23° 31'. Since the result is positive, the declination is 23° 31' East.
