If the magnetic bearing of the Sun at a certain place in the Southern Hemisphere during noon is 336° 29′, then the magnetic declination at that place is 

Discussion - MCQs on Compass Surveying - Magnetic Declination

If the magnetic bearing of the Sun at a certain place in the Southern Hemisphere during noon is 336° 29', then the magnetic declination at that place is __________.

A. 66° 29' W
B. 66° 29' E
C. 23° 31' E
D. 23° 31' W
Correct Answer: C. 23° 31' E

🧭 Understanding the Core Concept

The key to solving this problem is knowing the Sun's position at noon.

  • In the Northern Hemisphere, the Sun is due South at noon (True Bearing = 180°).
  • In the Southern Hemisphere, the Sun is due North at noon (True Bearing = 360° or 0°).

Magnetic Declination is the angle between True North and Magnetic North. It's the value you need to add or subtract from a Magnetic Bearing to get the True Bearing.

🔬 Step-by-Step Calculation

We can find the magnetic declination by comparing the known True Bearing of the sun with its measured Magnetic Bearing.

Given Data:

  • Location: Southern Hemisphere
  • Time: Noon
  • Magnetic Bearing of the Sun = 336° 29'

Step 1: Determine the True Bearing

Since the location is in the Southern Hemisphere at noon, the Sun is at True North.

Therefore, True Bearing = 360° 00'

Step 2: Calculate the Declination

Declination = True Bearing - Magnetic Bearing

Declination = 360° 00' - 336° 29'

To subtract, we borrow 1° from 360° and convert it to 60':

Declination = 359° 60' - 336° 29' = 23° 31'

Step 3: Determine the Direction (East or West)

The formula for declination is: True Bearing = Magnetic Bearing + Declination (East).

Since the Magnetic Bearing (336° 29') is less than the True Bearing (360°), we must add a positive value to it. A positive (East) declination is added.

Therefore, the declination is 23° 31' E.

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