The expression for the discharge (Q) through a flow net for isotropic soil is given by:

Q31: The expression for the discharge (Q) through a flow net for isotropic soil is given by:

A. Q = K · H × (Nf)/(ND)
B. Q = K · H \sqrt(Nf)/(ND)
C. Q = K · H ≤ft((Nf)/(ND)
D. Q = K · H ≤ft((Nf)/(ND)
Correct Answer: A. Q = K · H × (Nf)/(ND)

📝 Detailed Explanation

A flow net is a graphical solution to seepage problems, built from two families of curves — flow lines and equipotential lines — that together let engineers estimate the total discharge through a soil mass without solving the underlying differential equation directly.

✅ Why “Q = K·H·(Nf/Nd)” Is Correct

For an isotropic soil, the discharge through a flow net is given by Q = K·H × (shape factor), where the shape factor is the ratio of the number of flow channels (Nf) to the number of equipotential drops (Nd): Q = K·H·(Nf/Nd).

FLOW NET (schematic) flow lines (Nf) equipotential lines (Nd)

A flow net combines flow lines (paths water follows) and equipotential lines (lines of equal head), forming a grid of curvilinear squares. Discharge Q = K·H·(Nf/Nd), where H is the total head loss.

❌ Why the Other Options Are Wrong

  • Q = K·H·√(Nf/Nd): introduces an incorrect square root — the shape factor Nf/Nd enters the discharge formula directly (linearly), not under a square root.
  • Q = K·H·(Nf/Nd)³: introduces an incorrect cube — again, the shape factor appears as a simple first-power ratio, not raised to any power.
  • Q = K·H·(Nf/Nd)²: introduces an incorrect square — same issue as the other distractors, each testing whether the simple linear Nf/Nd ratio has been memorized precisely.

🔑 Key Point

The flow net discharge formula uses the shape factor Nf/Nd exactly as a simple ratio — no square roots, squares, or cubes involved — a detail worth fixing firmly in memory given how the distractors are constructed here.

💡 Key Concepts for Students

  • Nf (number of flow channels) and Nd (number of equipotential drops) are both simply COUNTED directly from a properly constructed flow net diagram — no separate formula is needed to obtain them.
  • H is the total head loss across the entire flow net (from upstream to downstream), not the head loss across just one equipotential drop.
  • This formula assumes an isotropic soil (permeability the same in all directions) — anisotropic soils require a modified approach, transforming the cross-section before drawing the flow net.
  • See the Going Deeper section for how a flow net is actually constructed and why it forms a grid of curvilinear squares.

📚 Going Deeper: Flow Nets: Construction and Interpretation

A flow net is a graphical technique for solving two-dimensional steady seepage problems — used, for instance, to estimate seepage discharge beneath a dam or through an earth embankment — without directly solving Laplace’s equation for potential flow.

ElementWhat It Represents
Flow linesPaths that individual water particles follow as they seep through the soil
Equipotential linesLines connecting points of equal total head (piezometric head) within the flow domain
Flow channelThe strip of soil between two adjacent flow lines
Equipotential dropThe head loss between two adjacent equipotential lines

A correctly drawn flow net has flow lines and equipotential lines crossing each other at right angles everywhere, forming a mesh of “curvilinear squares” (approximately square-shaped, though curved, cells). Once this net is drawn (traditionally by careful hand-sketching and iterative adjustment, though now often done computationally), simply counting the number of flow channels (Nf) and equipotential drops (Nd) is enough to estimate total seepage discharge via Q = K·H·(Nf/Nd) — a remarkably simple result for what is, underneath, a fairly complex boundary-value problem.

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