Structures·MCQ explained

In the cantilever truss shown (top chord A–B–C, 100 t load at B, vertical BD, members AD, ED, and CD at 30°), the force in member BC is:

Try it first: pick an option, then read the explanation.

Correct answer: C. zero

Asked in SSC JE 04/03/2017 (Evening)

Detailed Explanation

Apply the two-member rule at joint C, the free end of the cantilever truss.

Joint C: \(\Sigma F_y = 0 \Rightarrow F_{CD} = 0\); \(\Sigma F_x = 0 \Rightarrow F_{BC} + F_{CD}\cos30^\circ = 0 \Rightarrow F_{BC} = 0\).

Why “zero” Is Correct

With CD zero, BC has nothing to balance it horizontally, so BC = 0 — option (c).

100 tABCDE
Cantilever truss fixed to a wall at A and E. Top chord A–B–C, vertical BD, members AD and ED, and member CD inclined at 30° at C. A 100 t load acts at B. At the unloaded joint C, BC and CD are not collinear, so both carry zero force; BD then carries the full 100 t in compression.

Why the Other Options Are Wrong

  • A. 100 t compressive: 100 t compression is the force in BD.
  • B. 100 t tensile: No member at C carries 100 t.
  • D. indeterminate: Joint C gives the answer directly.

Key Point

Free-end joint with two non-collinear members and no load → both zero.

Key Concepts for Students

  • Adding a load at C would make BC and CD carry force.
  • Top chord AB of this cantilever truss is in tension.
  • Bottom members at the wall (ED) are in compression for downward loads.

Practice more: this is question 25 in Beams and Trusses MCQs – Part 2. Try the whole set and check every answer instantly.