Structures·MCQ explained

Point out the correct matching of beam and maximum deflection:

Try it first: pick an option, then read the explanation.

Correct answer: D. Cantilever, UDL w: wL⁴/(8EI)

Asked in SSC JE 2012

Detailed Explanation

Compare each option with the standard table of maximum deflections.

Why “Cantilever, UDL w: wL⁴/(8EI)” Is Correct

The cantilever with a UDL has δmax = wL⁴/(8EI) at the free end — option (d) is the only correct pair.

Beam and loadingMaximum slopeMaximum deflectionWhere
Cantilever, point load W at free endWL²/2EIWL³/3EIFree end
Cantilever, UDL w over full lengthwL³/6EIwL⁴/8EIFree end
Cantilever, triangular load (w at fixed end, 0 at free end)wL³/24EIwL⁴/30EIFree end
Cantilever, couple M at free endML/EIML²/2EIFree end
Simply supported, central point load WWL²/16EIWL³/48EISlope at supports, deflection at centre
Simply supported, UDL w over full spanwL³/24EI5wL⁴/384EISlope at supports, deflection at centre
Simply supported, equal end couples M (pure bending)ML/2EIML²/8EISlope at supports, deflection at centre

Standard results (EI constant). In a cantilever the slope and deflection are zero at the fixed end and maximum at the free end.

Why the Other Options Are Wrong

  • A. Simply supported beam, central point load W: WL³/(384EI): The simply supported central-load deflection is WL³/48EI.
  • B. Simply supported beam, UDL w: 3wL⁴/(384EI): The simply supported UDL deflection is 5wL⁴/384EI.
  • C. Cantilever, point load W at tip: WL³/(48EI): The cantilever tip-load deflection is WL³/3EI (48 belongs to the simply supported case).

Key Point

Cantilever UDL: wL⁴/8EI; cantilever tip load: WL³/3EI; SS central load: WL³/48EI; SS UDL: 5wL⁴/384EI.

Key Concepts for Students

  • Memorise the four basic deflection formulas — they solve most MCQs.
  • Swapped coefficients (3 ↔ 48) are a common trap.
  • Superposition combines these for multiple loads.

Practice more: this is question 39 in Slope and Deflection MCQs – Part 3. Try the whole set and check every answer instantly.