Structures·MCQ explained

What is the relation between equivalent length (Le) and actual length (l) for a column with one end fixed and the other free?

Try it first: pick an option, then read the explanation.

Correct answer: D. Le = 2l

Asked in SSC JE 23/09/2019 (Morning); SSC JE 24/01/2018 (Evening)

Detailed Explanation

Mirror the fixed–free column about its fixed base: the combined shape is a half sine wave of length 2l with zero moment at both tips — a pin-ended column of length 2l.

Why “Le = 2l” Is Correct

Hence Le = 2l, and P = π²EI/(4l²).

PBoth ends hingedle = LP = π²EI/L²PBoth ends fixedle = L/2P = 4π²EI/L²PFixed – freele = 2LP = π²EI/4L²PFixed – hingedle = L/√2P = 2π²EI/L²
Fixed–free column: Le = 2l.

Why the Other Options Are Wrong

  • A. Le = 3l: 3l is not a theoretical effective length for any standard case.
  • B. Le = 2.5l: 2.5l is not a standard value.
  • C. Le = l/4: l/4 is far too short; even fixed–fixed gives only l/2.

Key Point

Fixed–free: Le = 2l (largest effective length, smallest Euler load).

Key Concepts for Students

  • Le is the distance between inflection points on the buckled shape.
  • IS 800 also takes 2.0L for this case.
  • Doubling Le cuts the buckling load to one quarter.

Practice more: this is question 8 in Columns and Struts MCQs – Part 1. Try the whole set and check every answer instantly.