Structures·MCQ explained

As per Euler's theory, for which of the following end conditions is the longest effective length of a column obtained?

Try it first: pick an option, then read the explanation.

Correct answer: C. When one end of the column is fixed and the other end is free

Asked in SSC JE 05/06/2024 (9 am–11 am)

Detailed Explanation

The effective length is the length of an equivalent pin-ended column with the same buckling load — the distance between inflection points of the buckled shape.

Why “When one end of the column is fixed and the other end is free” Is Correct

A column fixed at the base and free at the top bends into a quarter sine wave; it behaves like half of a pin-ended column of length 2L, so le = 2L — the longest of all.

PBoth ends hingedle = LP = π²EI/L²PBoth ends fixedle = L/2P = 4π²EI/L²PFixed – freele = 2LP = π²EI/4L²PFixed – hingedle = L/√2P = 2π²EI/L²
Fixed–free (flagpole) column: le = 2L, the longest effective length and the lowest crippling load.

Why the Other Options Are Wrong

  • A. When both the ends of the column are hinged: Both hinged: le = L.
  • B. When one end of the column is fixed and the other end is hinged: Fixed–hinged: le = L/√2 ≈ 0.707L.
  • D. When both the ends of the column are fixed: Both fixed: le = L/2 — the shortest.

Key Point

le: fixed–free 2L > hinged–hinged L > fixed–hinged L/√2 > fixed–fixed L/2.

Key Concepts for Students

  • Longer le means a smaller Euler load (P ∝ 1/le²).
  • Fixed–free columns include flagpoles and cantilever posts.
  • IS 800 also recommends 2.0L for this case.

Practice more: this is question 3 in Columns and Struts MCQs – Part 1. Try the whole set and check every answer instantly.