Geotechnical·MCQ explained

In granular materials, the resistance to sliding on any plane within the soil mass depends upon the ______.

Try it first: pick an option, then read the explanation.

Correct answer: D. normal force and angle of internal friction

Asked in SSC JE 15/11/2022 (Shift-I)

Detailed Explanation

Granular soils behave like a block on a rough surface: the force needed to make it slide is proportional to how hard it is pressed against the surface. In soil terms, the shear strength on a plane is

\[ \tau_f = \sigma\tan\phi \]

Why “normal force and angle of internal friction” Is Correct

Two things appear in that equation: the normal stress σ (the normal force over the area) and the angle of internal friction φ. So the resistance to sliding depends on the normal force and φ.

στClay, φ = 0: τ = cSand, c = 0: τ = σ tan φ(passes through origin)c–φ soilccφ
Failure envelopes for the three kinds of soil. Pure clay under undrained loading (φ = 0): horizontal line at τ = c. Clean sand (c = 0): straight line through the origin at angle φ. Most real soils (c–φ soils): line with intercept c and slope φ.

Why the Other Options Are Wrong

  • A. normal force only: Normal force alone is not enough; the friction angle sets how much resistance each unit of normal force gives.
  • B. tangential force only: The tangential force is the applied shear, not the resistance.
  • C. tangential force and angle of sliding friction: Again the tangential force is the load, not what the resistance depends on.

Key Point

Friction resistance = normal force × tan φ.

Key Concepts for Students

  • Increasing confining pressure increases sand strength.
  • Effective normal stress must be used when pore water is present.
  • Interlocking in dense sands adds to the measured φ.

Practice more: this is question 18 in Shear Strength of Soils MCQs – Part 2. Try the whole set and check every answer instantly.