Structures·MCQ explained

According to the maximum strain energy theory, the yield locus is:

Try it first: pick an option, then read the explanation.

Correct answer: D. an ellipse

Asked in SSC JE 03/03/2017 (Evening)

Detailed Explanation

In two dimensions (σ₃ = 0), each theory of failure gives a closed boundary in the σ₁–σ₂ plane. Points inside are safe.

\[ \sigma_1^2 + \sigma_2^2 - 2\mu\,\sigma_1\sigma_2 = \sigma_y^2 \]

A quadratic with no linear terms and \(4\mu^2 < 4\) — an ellipse with its major axis along the 45° line.

Why “an ellipse” Is Correct

The strain energy theory gives an ellipse. (The von Mises distortion energy theory also gives an ellipse, with μ effectively 0.5.)

σ₁/σyσ₂/σyRankine (max principal stress): squareTresca/Guest (max shear stress): hexagonvon Mises (shear strain energy): ellipseHaigh (total strain energy, μ = 0.3): ellipse
Yield loci in the σ₁–σ₂ plane: Rankine gives a square, Tresca a hexagon inscribed in the von Mises ellipse, and Haigh's total strain energy theory another ellipse.

Why the Other Options Are Wrong

  • A. a rectangle: Rankine's theory gives a square, not a general rectangle.
  • B. a circle: None of the standard theories gives a circle in the σ₁–σ₂ plane.
  • C. a hexagon: A hexagon is Tresca's locus.

Key Point

Yield loci: Rankine square, St. Venant rhombus, Tresca hexagon, Haigh and von Mises ellipses.

Key Concepts for Students

  • Von Mises ellipse: σ₁² + σ₂² − σ₁σ₂ = σy².
  • Tresca's hexagon is inscribed in the von Mises ellipse.
  • Ellipses are elongated along σ₁ = σ₂.

Practice more: this is question 23 in Principal Stress and Principal Planes MCQs – Part 2. Try the whole set and check every answer instantly.