For a retaining wall, the Mohr circle radius for active earth pressure is ______ the Mohr circle radius for passive earth pressure.
Try it first: pick an option, then read the explanation.
Asked in SSC JE 06/06/2024 (Morning)
Detailed Explanation
Think of a soil element at a given depth behind a wall. Its vertical stress σv = γz is fixed. Only the horizontal stress changes as the wall moves.
Active radius: \(r_a = \tfrac{1}{2}\sigma_v(1 - K_a)\). Passive radius: \(r_p = \tfrac{1}{2}\sigma_v(K_p - 1)\).
For \(\phi = 30^\circ\): \(r_a = \tfrac{1}{2}\sigma_v(1 - \tfrac13) = 0.33\sigma_v\); \(r_p = \tfrac{1}{2}\sigma_v(3 - 1) = \sigma_v\).
Why “less than” Is Correct
In the active state σv is the major principal stress and the horizontal stress drops until the circle touches the envelope — a small circle. In the passive state σv becomes the minor principal stress and the horizontal stress must climb much higher before the circle touches the envelope — a large circle. So the active radius is always less than the passive radius.
Why the Other Options Are Wrong
- A. more or less depending on the angle of internal friction of soil: For any φ > 0 the passive circle is larger; it does not switch with φ.
- B. more than: The active circle is the smaller one.
- C. equal to: They are equal only if φ = 0, which gives no frictional strength at all.
Key Point
Active: σv is σ₁. Passive: σv is σ₃. Passive circle is much larger.
Key Concepts for Students
- Both circles touch the same failure envelope.
- The at-rest circle lies inside, below the envelope.
- Failure planes: 45° + φ/2 to horizontal (active), 45° − φ/2 (passive).
Practice more: this is question 4 in Earth Pressure and Retaining Wall MCQs – Part 1. Try the whole set and check every answer instantly.