Structures·MCQ explained

The predominant effect of an axial tensile force on a (close-coiled) helical spring is:

Try it first: pick an option, then read the explanation.

Correct answer: D. Twisting

Asked in SSC JE 2012

Detailed Explanation

Cut the spring across one coil. To keep the lower part in equilibrium, the wire section must carry a force W and a moment W·R about the wire's own axis, because the load line (the spring axis) is a distance R away.

Why “Twisting” Is Correct

In a close-coiled spring the helix angle is tiny, so that moment acts almost exactly about the wire axis: it is a torque. The predominant effect is twisting; the direct shear W is small in comparison.

WWD (mean)n coils, mean coil radius R = D/2, wire diameter dT = W·D/2WdWire sectionτ = 16WR/(πd³), δ = 64WR³n/(Gd⁴)
Close-coiled helical spring under axial load W: every wire section carries a torque W·R (R = D/2) plus a small direct shear W.

Why the Other Options Are Wrong

  • A. Bending: Bending is negligible in a close-coiled spring under axial load (it appears under an axial torque, or in open-coiled springs).
  • B. Tension: The wire does not carry axial tension; the force on each section is a shear W.
  • C. Compression: There is no axial compression in the wire.

Key Point

Close-coiled spring under axial load → wire in torsion: τ = 16WR/πd³.

Key Concepts for Students

  • Spring deflection comes from wire twist.
  • Direct shear 4W/πd² is a small correction.
  • Wahl's factor adds curvature and direct-shear effects.

Practice more: this is question 3 in Spring MCQs – Part 1. Try the whole set and check every answer instantly.