Structures·MCQ explained

The radius of gyration of a rectangular section (depth D, width B) about a centroidal axis parallel to the width is:

Try it first: pick an option, then read the explanation.

Correct answer: C. D/(2√3)

Asked in SSC JE 23/01/2018 (Evening)

Detailed Explanation

Radius of gyration r is the distance at which the whole area could be concentrated to give the same moment of inertia: I = A r².

\[ r = \sqrt{\frac{I}{A}} = \sqrt{\frac{BD^3/12}{BD}} = \sqrt{\frac{D^2}{12}} = \frac{D}{2\sqrt3} \approx 0.289D \]

Why “D/(2√3)” Is Correct

About the axis parallel to the width, the depth D is the dimension that matters, giving D/(2√3). The width B cancels out.

SectionI about centroidal axisy maxSection modulus Z
Rectangle b × d (axis ∥ b)bd³/12d/2bd²/6
Square side a (sides horizontal)a⁴/12a/2a³/6
Square side a (diagonal horizontal)a⁴/12a/√2a³/(6√2)
Solid circle, diameter dπd⁴/64d/2πd³/32
Triangle b × h (axis ∥ base)bh³/362h/3bh²/24
Hollow circle D, dπ(D⁴ − d⁴)/64D/2π(D⁴ − d⁴)/(32D)

Why the Other Options Are Wrong

  • A. D/2: D/2 is the distance to the extreme fibre, not the radius of gyration.
  • B. D/√3: D/√3 is the radius of gyration about the base (I = BD³/3).
  • D. D/(4√3): D/(4√3) is half the correct value.

Key Point

Rectangle: r = D/(2√3) ≈ 0.289D about the centroidal axis parallel to B.

Key Concepts for Students

  • Circle: r = d/4.
  • Columns buckle about the axis of least r.
  • Slenderness ratio = effective length / least radius of gyration.

Practice more: this is question 19 in Bending and Shear Stress MCQs – Part 2. Try the whole set and check every answer instantly.