Problem Statement
The specific energy for a 6 m wide rectangular channel is to be 5 kg-m/kg. If the rate of flow of water through the channel is 24 m³/s, determine the alternate depths of flow.
Given Data & Constants
- Width of channel, \(B = 6 \, \text{m}\)
- Specific Energy, \(E = 5 \, \text{kg-m/kg} = 5 \, \text{m}\)
- Discharge, \(Q = 24 \, \text{m}^3/\text{s}\)
- Acceleration due to gravity, \(g = 9.81 \, \text{m/s}^2\)
Solution
1. Calculate Discharge per Unit Width (q)
2. Set up the Specific Energy Equation
The specific energy equation relates the depth, velocity, and specific energy. We can express velocity in terms of the discharge per unit width (\(V = q/d\)).
Rearranging this gives a cubic equation in terms of depth (d).
3. Solve for the Alternate Depths (d)
This cubic equation must be solved by trial and error or using a numerical solver. The equation will have two positive roots, which are the alternate depths.
By solving the equation, we find the two depths:
The alternate depths of flow are approximately 4.96 m and 0.41 m.
Explanation of Alternate Depths
For any given discharge in an open channel, there is a certain amount of specific energy (\(E\)). Unless the flow is at the critical depth (where specific energy is at a minimum), there are always two possible depths at which the flow can have that same amount of specific energy. These are known as **alternate depths**.
- Subcritical Flow (\(d_1\)): This is a deep, slow-moving flow. The potential energy (depth) is high, and the kinetic energy (velocity) is low.
- Supercritical Flow (\(d_2\)): This is a shallow, fast-moving flow. The potential energy (depth) is low, and the kinetic energy (velocity) is high.
A flow can transition between these two states through a hydraulic jump (from supercritical to subcritical) or over a smooth weir (from subcritical to supercritical).
