Calculate the pressures at A, B, C and D in the fig.

Calculate the pressures at A, B, C and D in the fig.

Problem Statement

Calculate the pressures at points A, B, C, and D in the figure. Assume the tube is filled with oil of specific gravity \( 0.9 \).

Solution

Given:

  • Specific weight of water (\( \gamma \)) = \( 9810 \, \text{N/m}^3 \)
  • Specific gravity of oil = \( 0.9 \)
  • Specific weight of oil (\( \gamma_{\text{oil}} \)) = \( 0.9 \times 9810 = 8829 \, \text{N/m}^3 \)
  • Take atmospheric pressure as 0 for gauge pressure.

Pressure at A (\( P_A \)):

Using the hydrostatic pressure equation:

\( P_A = 0 – \gamma h_{\text{between X and A}} \)

Substitute the values:

\( P_A = – (9810 \times 0.8) \)

Final Value:

\( P_A = -7848 \, \text{Pa} \)

Pressure at B (\( P_B \)):

Using the hydrostatic pressure equation:

\( P_B = 0 + \gamma h_{\text{between X and B}} \)

Substitute the values:

\( P_B = 9810 \times 0.5 \)

Final Value:

\( P_B = 4905 \, \text{Pa} \)

Neglecting air, the pressure at C (\( P_C \)) is:

\( P_C = P_B = 4905 \, \text{Pa} \)

Pressure at D (\( P_D \)):

Using the hydrostatic pressure equation:

\( P_D = P_C + \gamma_{\text{oil}} h_{\text{between C and D}} \)

Substitute the values:

\( P_D = 4905 + (8829 \times 1.9) \)

Final Value:

\( P_D = 21680 \, \text{Pa} \)

Explanation

This problem involves calculating the pressures at different points within a fluid-filled tube using hydrostatic principles:

  1. The pressure at A (\( P_A \)) is calculated as negative due to the height of water above it, relative to atmospheric pressure.
  2. The pressure at B (\( P_B \)) is determined by the height of the water column from point X to B.
  3. Since air pressure is neglected, the pressure at C (\( P_C \)) is equal to \( P_B \).
  4. The pressure at D (\( P_D \)) is calculated by adding the pressure contribution from the oil column between points C and D to \( P_C \).

Physical Meaning

  1. Specific Weight: The specific weight of a fluid determines the pressure it exerts for a given height. Here, oil’s specific weight is less than water’s, leading to different pressure contributions.
  2. Gauge Pressure: All calculations assume atmospheric pressure as the reference (0 gauge pressure), simplifying the analysis.
  3. Layered Fluids: The pressure at different points depends on the height and specific weight of the fluids present in the column.

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