A vessel has two identical orifices provided in one of its sides as shown in the figure. Locate the point of intersection of the two jets. Take Cv = 0.98 for both orifices.

Intersection of Two Jets Analysis

Intersection of Two Jets Analysis

Problem Statement

A vessel has two identical orifices provided in one of its sides as shown in the figure. Locate the point of intersection of the two jets. Take Cv = 0.98 for both orifices.

Vessel with two identical orifices

Given Data

Coefficient of velocity (Cv) 0.98
Relationship between orifice heights Y1 = 2.5 Y2
Difference in heights (Y1 – Y2) 3 m

1. Establishing the Range Formula

For each orifice, the horizontal range (x) of the jet is given by:

x = Cv × √(4Y H)

Since both jets have the same Cv and intersect at the same horizontal distance, we equate:

x/√(4Y1 H1) = x/√(4Y2 H2)

Which simplifies to:

Y1 H1 = Y2 H2

2. Relating the Heights

Given the relationship:

Y1 = 2.5 Y2

And the difference in heights:

Y1 – Y2 = 3 m

Substituting the first into the second:

(2.5Y2 – Y2) = 3
1.5Y2 = 3
Y2 = 2 m
Y1 = 2.5 × 2 = 5 m

3. Calculating the Intersection Point

Using the range formula for one jet:

x = Cv × √(4Y1 H1)

Assuming the head H1 is 2 m (associated with Y1 = 5 m), we have:

x = 0.98 × √(4 × 5 × 2)
x = 0.98 × √(40)
x ≈ 0.98 × 6.32 ≈ 6.2 m
x ≈ 6.2 m

Conclusion

The point of intersection of the two jets is located approximately 6.2 m from the orifice along the horizontal direction.

By using the relationship between the orifice heights (Y1 = 2.5 Y2) and the given height difference (3 m), we determined Y1 = 5 m and Y2 = 2 m. This allowed us to calculate the horizontal range using the formula x = Cv × √(4Y H).

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