Determine the magnitude of resultant force and its direction on the vane shown in the figure below if a water of jet 50mm diameter and 20m/s velocity strikes the vane tangentially and deflects without friction.

Determine the magnitude of resultant force and its direction on the vane shown in the figure below if a water jet of 50mm diameter and 20m/s velocity strikes the vane tangentially and deflects without friction.

Pipe Bend Force Calculation – Fluid Mechanics Solution

Water Jet Impact on Vane

Fluid Mechanics Problem Solution

Problem Statement

Determine the magnitude of resultant force and its direction on the vane shown in the figure below if a water jet of 50mm diameter and 20m/s velocity strikes the vane tangentially and deflects without friction.

Water jet striking vane diagram

Given Data

Jet diameter (d) 50 mm = 0.05 m
Jet velocity (V) 20 m/s
Fluid Water (density ρ = 1000 kg/m³)
Condition No friction (no loss of energy)
Pressure Atmospheric (no pressure force)
Deflection angle 45° (based on the figure)

Solution Approach

To find the resultant force exerted on the vane by the water jet, we need to:

  1. Calculate the cross-sectional area of the jet and the discharge
  2. Apply the momentum equation to determine the forces in both X and Y directions
  3. Calculate the resultant force and its direction

Preliminary Calculations

Step 1: Calculate the cross-sectional area of the jet:

A = π/4 × d² = π/4 × 0.05² = 0.001963 m²

Step 2: Calculate the discharge:

Q = A × V = 0.001963 × 20 = 0.03927 m³/s

Step 3: Note the key conditions:

  • No friction means there is no loss of energy
  • Pressure is atmospheric, so there are no pressure forces
  • Velocity magnitude remains constant throughout (V = 20 m/s)

Force in X-Direction

Step 1: Apply the momentum equation in the X-direction:

Fx = ρQ(V1x – V2x)

Step 2: Determine the X-components of velocity:

  • Initial velocity (V1x) = 20 m/s (straight to the right)
  • Final velocity (V2x) = -20cos45° = -20 × 0.7071 = -14.142 m/s (negative direction)

Step 3: Calculate Fx:

Fx = ρQ(V1x – V2x) = 1000 × 0.03927 × (20 – (-14.142))
Fx = 1000 × 0.03927 × 34.142 = 1340.8 N

Force in Y-Direction

Step 1: Apply the momentum equation in the Y-direction:

Fy = ρQ(V1y – V2y)

Step 2: Determine the Y-components of velocity:

  • Initial velocity (V1y) = 0 m/s (no vertical component initially)
  • Final velocity (V2y) = -20sin45° = -20 × 0.7071 = -14.142 m/s (downward direction)

Step 3: Calculate Fy:

Fy = ρQ(V1y – V2y) = 1000 × 0.03927 × (0 – (-14.142))
Fy = 1000 × 0.03927 × 14.142 = 555.4 N

Resultant Force Calculation

Step 1: Calculate the magnitude of the resultant force:

FR = √(Fx² + Fy²)
FR = √(1340.8² + 555.4²)
FR = √(1797745.64 + 308469.16)
FR = √2106214.8 = 1451 N

Step 2: Calculate the direction of the resultant force:

θ = tan⁻¹(Fy/Fx) = tan⁻¹(555.4/1340.8) = 22.5°
The resultant force exerted on the vane is 1451 N at an angle of 22.5° from the horizontal.

Summary

  • The water jet has:
    • Diameter: 50 mm
    • Velocity: 20 m/s
    • Cross-sectional area: 0.001963 m²
    • Discharge: 0.03927 m³/s
  • The force components were calculated using the momentum equation:
    • X-direction force: Fx = 1340.8 N
    • Y-direction force: Fy = 555.4 N
  • The resultant force on the vane:
    • Magnitude: 1451 N
    • Direction: 22.5° from the horizontal axis

This problem demonstrates the application of the momentum principle to determine forces on a curved vane. The water jet changes direction without losing energy (no friction), resulting in a change of momentum that produces a force on the vane. The magnitude and direction of this force were calculated by analyzing the X and Y components separately.

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