Calculate the weight of a ball of diameter 50mm which is just supported in a vertical air stream which is flowing at a velocity of 10 m/s. Take density of air = 1.25kg/m³ and kinematic viscosity = 15 stokes.

Fluid Mechanics Problem Solution

Problem Statement

Calculate the weight of a ball of diameter 50mm which is just supported in a vertical air stream which is flowing at a velocity of 10 m/s. Take density of air = 1.25kg/m³ and kinematic viscosity = 15 stokes.

Given Data

Diameter of ball (D) 50 mm = 0.05 m
Cross-sectional area of ball (A) π/4 × (0.05)² = 0.001963 m²
Density of air (ρ) 1.25 kg/m³
Kinematic viscosity (ν) 15 stokes = 15 × 10⁻⁴ m²/s
Velocity of air stream (V) 10 m/s

Solution Approach

To determine the weight of the ball, we need to recognize that when the ball is just supported in the vertical air stream, the drag force acting upward on the ball exactly balances the weight of the ball acting downward. We’ll calculate the Reynolds number to determine the appropriate drag coefficient, then find the drag force which equals the weight of the ball.

Calculations

Reynolds Number Calculation

Step 1: Calculate the Reynolds number (Re) using the formula:

Re = VD/ν = (10 × 0.05)/(15 × 10⁻⁴) = 333.33

Since Re = 333.33 falls between 5 and 1000, we can use the drag coefficient (CD) value of 0.4 for a sphere in this flow regime.

Step 2: Calculate the drag force using the drag equation:

FD = ½ CD ρAV² = ½ × 0.4 × 1.25 × 0.001963 × 10²
FD = ½ × 0.4 × 1.25 × 0.001963 × 100
FD = 0.4 × 1.25 × 0.001963 × 50
FD = 0.049075 N ≈ 0.049 N

Step 3: Since the ball is just supported in the air stream, the drag force exactly equals the weight of the ball:

Weight of ball = FD = 0.049 N

Weight of the ball = 0.049 N

Detailed Explanation

Physical Principles

This problem involves the balance of forces on a spherical object in a fluid stream. When the ball is just supported in the vertical air stream, it reaches a state of equilibrium where the upward drag force exactly equals the downward gravitational force (weight).

Reynolds Number and Flow Regime

The Reynolds number (Re = 333.33) indicates that the flow around the ball is in the transitional regime between laminar and turbulent flow. In this range (5 < Re < 1000), the drag coefficient for a sphere is approximately constant at CD = 0.4.

Drag Force Analysis

The drag force on a spherical object in a fluid stream is given by the equation:

FD = ½ CD ρAV²

Where:

  • CD is the drag coefficient (0.4 in this case)
  • ρ is the fluid density (1.25 kg/m³)
  • A is the projected area of the sphere (π/4 × D² = 0.001963 m²)
  • V is the fluid velocity (10 m/s)

Force Balance

In this equilibrium condition:

Weight of ball = Drag force = 0.049 N

Practical Applications

This principle of force balance between drag and weight is utilized in various engineering applications:

  • Fluid bed reactors where solid particles are suspended in a fluid stream
  • Aerodynamic testing of objects in wind tunnels
  • Design of parachutes and air resistance devices
  • Particle classification systems in mineral processing
  • Pneumatic conveying systems in industrial applications

Mass of the Ball

If we wanted to determine the mass of the ball, we could use the relation:

Weight = mass × gravitational acceleration
0.049 N = mass × 9.81 m/s²
mass = 0.049 N ÷ 9.81 m/s² ≈ 0.005 kg = 5 grams

Understanding these principles of fluid dynamics and force equilibrium is crucial in aerospace engineering, mechanical design, and environmental studies where objects interact with fluid flows.

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top