To measure a baseline, a steel tape 30m long, standardized at 15°C with a pull of 100 N, was used. Find the correction per tape length if the temperature at the time of measurement was 20°C and the pull exerted was 160 N. The weight of 1 cubic cm of steel is 0.0786 N, the total weight of the tape is 8 N, the modulus of elasticity (E) is 2.1 × 10⁵ N/mm² and the coefficient of expansion (α) is 7.1 × 10⁻⁷ per °C.

Problem Statement

To measure a baseline, a steel tape 30m long, standardised at 15°C with a pull of 100 N, was used. Find the correction per tape length if the temperature at the time of measurement was 20°C and the pull exerted was 160 N. The weight of 1 cubic cm of steel is 0.0786 N, the total weight of the tape is 8 N, the modulus of elasticity (E) is 2.1 × 10⁵ N/mm² (assumed based on typical values), and the coefficient of expansion (α) is 7.1 × 10⁻⁷ per °C.

Step-by-Step Solution

Key Information

  • Nominal Tape Length (Lnom) = 30 m = 3000 cm
  • Standard Temperature (To) = 15°C
  • Standard Pull (Po) = 100 N
  • Measurement Temperature (Tm) = 20°C
  • Measurement Pull (Pm) = 160 N
  • Density of Steel (ρ) = 0.0786 N/cm³
  • Total Weight of Tape (W) = 8 N
  • Modulus of Elasticity (E) = 2.1 × 10⁵ N/mm² (Assumed unit for consistency)
  • Coefficient of Thermal Expansion (α) = 7.1 × 10⁻⁷ /°C
  • Goal: Find the Total Correction per Tape Length (Ctotal).

Step 1: Calculate Tape Cross-Sectional Area (A)

The area (A) is needed for the pull correction. We can find it using the tape’s weight, length, and the density of steel.

Weight (W) = Volume × Density = (Area × Length) × Density

A = W / (Lengthcm × ρ)

A = 8 N / (3000 cm × 0.0786 N/cm³)

A = 8 / 235.8 cm²

A ≈ 0.03393 cm²

Convert to mm² for use with E:

A ≈ 0.03393 cm² × (10 mm/cm)² = 3.393 mm²

Using rounded value A ≈ 3.39 mm² (or 0.034 cm² as in the original solution text)

Step 2: Calculate Pull Correction per Tape Length (Cp)

Calculate the stretch due to the difference in pull using the calculated Area (A) and given Modulus of Elasticity (E).

Cp = (Pm – Po) Lnom / (A × E)

Using A ≈ 3.39 mm² and E = 2.1 × 10⁵ N/mm²:

Cp = (160 N – 100 N) × 30 m / (3.39 mm² × 2.1 × 10⁵ N/mm²)

Cp = (60 N) × 30 m / (7.119 × 10⁵ N)

Cp = 1800 m / (7.119 × 10⁵)

Cp ≈ +0.00253 m

(Rounding consistent with original solution gives Cp ≈ +0.0025 m)

(Positive sign indicates stretching)

Step 3: Calculate Temperature Correction per Tape Length (Ct)

Calculate the expansion due to the temperature difference.

Ct = α (Tm – To) Lnom

Ct = (7.1 × 10⁻⁷ /°C) × (20°C – 15°C) × 30 m

Ct = (7.1 × 10⁻⁷) × (5) × 30 m

Ct = +0.0001065 m

(Positive sign indicates expansion)

Step 4: Calculate Total Correction per Tape Length (Ctotal)

Sum the individual corrections algebraically.

Ctotal = Cp + Ct

Using rounded values consistent with the original solution (Cp≈0.0025, Ct≈0.0001):

Ctotal ≈ 0.0025 m + 0.0001065 m

Ctotal ≈ +0.0026 m

(This represents the net lengthening of the tape per 30m nominal length under measurement conditions)

Final Result

The total correction per tape length is approximately +0.0026 metres.

Conceptual Explanation & Applications

Core Concepts:

  • Deriving Physical Properties: When a direct property like cross-sectional area (A) isn’t given, it can sometimes be calculated from other knowns like total weight (W), length (L), and material density (ρ) using the relationship W = A × L × ρ.
  • Tape Standardization: Tapes are calibrated for a nominal length (Lnom) under standard temperature (To) and pull (Po).
  • Thermal Expansion (α): Temperature differences (Tm – To) cause length changes proportional to α and Lnom.
  • Elasticity (E) & Tension Effects: Pull differences (Pm – Po) cause stretching/relaxation proportional to Lnom and inversely proportional to Area (A) and Modulus of Elasticity (E).
  • Combined Corrections: The net effect on tape length is the algebraic sum of individual corrections due to different physical factors (temperature, pull, sag, etc.).

Real-World Applications:

  • Precise Engineering Surveys: Calculating corrections is standard practice when high accuracy is needed for setting out structures, alignments, etc.
  • Geodetic Control & Monitoring: Essential for high-precision measurements where environmental factors significantly impact results.
  • Calibration & Metrology: Understanding how to derive and apply corrections is fundamental in calibrating measuring instruments.
  • Forensic Engineering: Analyzing measurement data where original instrument specifications might be incomplete requires deriving properties if possible.
  • Quality Control: Assessing the impact of environmental variations on measurements in various industrial and scientific settings.

Why It Works:
The goal is to find the total change in the tape’s length due to differences between field conditions (20°C, 160 N) and standard conditions (15°C, 100 N). First, the cross-sectional area (A) of the tape is calculated because it’s essential for the pull correction formula. Using the tape’s total weight, length, and the density of steel, A is found to be approximately 3.39 mm². Second, the temperature correction (Ct) is calculated. The field temperature is higher than standard (20°C > 15°C), causing the tape to expand by +0.0001065 m per 30m length. Third, the pull correction (Cp) is calculated. The pull applied in the field is greater than standard (160 N > 100 N), causing the tape to stretch elastically. Using the calculated area (A) and the modulus of elasticity (E), this stretch is found to be approximately +0.0025 m per 30m length. Finally, the total correction per tape length (Ctotal) is the sum of the individual corrections. Since both corrections are positive (lengthening), Ctotal = Ct + Cp ≈ +0.0001 m + +0.0025 m = +0.0026 m. This means that under the measurement conditions, the 30m tape was effectively 0.0026 m longer than its standard length.

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