Problem Statement
To measure a baseline, a steel tape 30m long, standardised at 15°C with a pull of 100 N, was used. Find the correction per tape length if the temperature at the time of measurement was 20°C and the pull exerted was 160 N. The weight of 1 cubic cm of steel is 0.0786 N, the total weight of the tape is 8 N, the modulus of elasticity (E) is 2.1 × 10⁵ N/mm² (assumed based on typical values), and the coefficient of expansion (α) is 7.1 × 10⁻⁷ per °C.
Step-by-Step Solution
Key Information
- Nominal Tape Length (Lnom) = 30 m = 3000 cm
- Standard Temperature (To) = 15°C
- Standard Pull (Po) = 100 N
- Measurement Temperature (Tm) = 20°C
- Measurement Pull (Pm) = 160 N
- Density of Steel (ρ) = 0.0786 N/cm³
- Total Weight of Tape (W) = 8 N
- Modulus of Elasticity (E) = 2.1 × 10⁵ N/mm² (Assumed unit for consistency)
- Coefficient of Thermal Expansion (α) = 7.1 × 10⁻⁷ /°C
- Goal: Find the Total Correction per Tape Length (Ctotal).
Step 1: Calculate Tape Cross-Sectional Area (A)
The area (A) is needed for the pull correction. We can find it using the tape’s weight, length, and the density of steel.
Weight (W) = Volume × Density = (Area × Length) × Density
A = W / (Lengthcm × ρ)
A = 8 N / (3000 cm × 0.0786 N/cm³)
A = 8 / 235.8 cm²
A ≈ 0.03393 cm²
Convert to mm² for use with E:
A ≈ 0.03393 cm² × (10 mm/cm)² = 3.393 mm²
Using rounded value A ≈ 3.39 mm² (or 0.034 cm² as in the original solution text)
Step 2: Calculate Pull Correction per Tape Length (Cp)
Calculate the stretch due to the difference in pull using the calculated Area (A) and given Modulus of Elasticity (E).
Cp = (Pm – Po) Lnom / (A × E)
Using A ≈ 3.39 mm² and E = 2.1 × 10⁵ N/mm²:
Cp = (160 N – 100 N) × 30 m / (3.39 mm² × 2.1 × 10⁵ N/mm²)
Cp = (60 N) × 30 m / (7.119 × 10⁵ N)
Cp = 1800 m / (7.119 × 10⁵)
Cp ≈ +0.00253 m
(Rounding consistent with original solution gives Cp ≈ +0.0025 m)
(Positive sign indicates stretching)
Step 3: Calculate Temperature Correction per Tape Length (Ct)
Calculate the expansion due to the temperature difference.
Ct = α (Tm – To) Lnom
Ct = (7.1 × 10⁻⁷ /°C) × (20°C – 15°C) × 30 m
Ct = (7.1 × 10⁻⁷) × (5) × 30 m
Ct = +0.0001065 m
(Positive sign indicates expansion)
Step 4: Calculate Total Correction per Tape Length (Ctotal)
Sum the individual corrections algebraically.
Ctotal = Cp + Ct
Using rounded values consistent with the original solution (Cp≈0.0025, Ct≈0.0001):
Ctotal ≈ 0.0025 m + 0.0001065 m
Ctotal ≈ +0.0026 m
(This represents the net lengthening of the tape per 30m nominal length under measurement conditions)
Final Result
Conceptual Explanation & Applications
Core Concepts:
- Deriving Physical Properties: When a direct property like cross-sectional area (A) isn’t given, it can sometimes be calculated from other knowns like total weight (W), length (L), and material density (ρ) using the relationship W = A × L × ρ.
- Tape Standardization: Tapes are calibrated for a nominal length (Lnom) under standard temperature (To) and pull (Po).
- Thermal Expansion (α): Temperature differences (Tm – To) cause length changes proportional to α and Lnom.
- Elasticity (E) & Tension Effects: Pull differences (Pm – Po) cause stretching/relaxation proportional to Lnom and inversely proportional to Area (A) and Modulus of Elasticity (E).
- Combined Corrections: The net effect on tape length is the algebraic sum of individual corrections due to different physical factors (temperature, pull, sag, etc.).
Real-World Applications:
- Precise Engineering Surveys: Calculating corrections is standard practice when high accuracy is needed for setting out structures, alignments, etc.
- Geodetic Control & Monitoring: Essential for high-precision measurements where environmental factors significantly impact results.
- Calibration & Metrology: Understanding how to derive and apply corrections is fundamental in calibrating measuring instruments.
- Forensic Engineering: Analyzing measurement data where original instrument specifications might be incomplete requires deriving properties if possible.
- Quality Control: Assessing the impact of environmental variations on measurements in various industrial and scientific settings.
Why It Works:
The goal is to find the total change in the tape’s length due to differences between field conditions (20°C, 160 N) and standard conditions (15°C, 100 N).
First, the cross-sectional area (A) of the tape is calculated because it’s essential for the pull correction formula. Using the tape’s total weight, length, and the density of steel, A is found to be approximately 3.39 mm².
Second, the temperature correction (Ct) is calculated. The field temperature is higher than standard (20°C > 15°C), causing the tape to expand by +0.0001065 m per 30m length.
Third, the pull correction (Cp) is calculated. The pull applied in the field is greater than standard (160 N > 100 N), causing the tape to stretch elastically. Using the calculated area (A) and the modulus of elasticity (E), this stretch is found to be approximately +0.0025 m per 30m length.
Finally, the total correction per tape length (Ctotal) is the sum of the individual corrections. Since both corrections are positive (lengthening), Ctotal = Ct + Cp ≈ +0.0001 m + +0.0025 m = +0.0026 m. This means that under the measurement conditions, the 30m tape was effectively 0.0026 m longer than its standard length.


