Water Resources·MCQ explained

The ratio of specific weight of a liquid to the specific weight of pure water at a standard temperature is called:

Try it first: pick an option, then read the explanation.

Correct answer: B. specific gravity of liquid

Asked in SSC JE 2012

Detailed Explanation

In fluid mechanics, comparing a liquid's weight density to a standard reference fluid provides a convenient dimensionless ratio.

\[ \text{Specific gravity } (S) = \frac{\text{Specific weight of liquid}}{\text{Specific weight of water at } 4^\circ\text{C}} = \frac{\gamma_{\text{liquid}}}{\gamma_{\text{water}}} = \frac{\rho_{\text{liquid}}}{\rho_{\text{water}}} \]

Why “specific gravity of liquid” Is Correct

By definition, the ratio of specific weight (or density) of a liquid to that of pure water at 4°C is the specific gravity (relative density) of the liquid.

PropertyFormulaSI unitStandard value (water, 4°C)
Density ρm/Vkg/m³1000 kg/m³
Specific weight γρgN/m³9810 N/m³
Specific gravity Sρ/ρ_water—1.0
Specific volume v1/ρm³/kg0.001 m³/kg
Bulk modulus K−dp/(dV/V)Pa2.06 GPa
Compressibility β1/KPa⁻¹4.85 × 10⁻¹⁰ Pa⁻¹

Why the Other Options Are Wrong

  • A. density of liquid: Density of liquid is mass per unit volume (kg/m³), which has units.
  • C. compressibility of liquid: Compressibility is the reciprocal of bulk modulus (Pa⁻¹).
  • D. surface tension of liquid: Surface tension is force per unit length (N/m).

Key Point

Specific gravity = Specific weight of liquid / Specific weight of water at standard temperature.

Key Concepts for Students

  • Pure water at 4°C has specific weight γ = 9810 N/m³ and density ρ = 1000 kg/m³.
  • Specific gravity is a pure dimensionless number.
  • Also called relative density.

Practice more: this is question 75 in Properties of Fluid MCQs – Part 5. Try the whole set and check every answer instantly.