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Shear Strength of Soils MCQs – Part 1

15 questions. Tap an option to check it instantly, then read the solution.

Practice SSC JE and other civil engineering exam questions on the shear strength of soils: the Mohr–Coulomb failure criterion, Mohr circles, cohesion and angle of internal friction, effective stress, and the direct shear, triaxial (UU, CU, CD), unconfined compression and vane shear tests. Tap an option to check it, then open the full explanation for each question.

Question 1Medium
Which of the following statements are correct with respect to Mohr–Coulomb failure criteria on soils? I. Mohr failure envelope is approximated as a straight line but in actual, it is curved. II. Mohr failure envelope is approximated as a curved line but in actual, it is straight. III. The Mohr circle drawn for soil cannot cross the Mohr failure envelope. IV. Cohesion c and angle of internal friction φ are fundamental properties of soil and are independent of testing conditions.
Full explanation

Answer: D. I and III

The true envelope is slightly curved but is taken as a straight line (I true). A Mohr circle cannot cross the envelope, because that would mean a stress state beyond failure (III true). c and φ depend on drainage and test conditions (IV false).

Question 2Medium
According to the Mohr–Coulomb failure criterion in soils, which of the following statements are INCORRECT? A. Shear strength is attributable to the interlocking of soil particles and cohesion. B. Shear strength is only attributable to the internal friction between particles. C. The Y-intercept represents friction of soils. D. The Mohr–Coulomb failure envelope is a straight line.
Full explanation

Answer: B. B and C

Strength comes from cohesion plus friction/interlocking, not friction alone (B incorrect). The y-intercept of the envelope is cohesion c, not friction (C incorrect). A and D are correct.

Question 3Easy
In the direct shear test conducted on soils, a proving ring is used to ______.
Full explanation

Answer: A. measure the magnitude of shear load

The proving ring is a calibrated steel ring; its deflection (read on a dial) gives the shear load on the specimen.

Question 4Medium
A sample of soil failed in a triaxial test under a deviator stress of 200 kN/m² when the confining pressure was 100 kN/m². If, for the sample, the confining pressure had been 200 kN/m², what would have been the deviator stress at failure? (Assume φ = 0.)
Full explanation

Answer: B. 200 kN/m²

With φ = 0, \(\sigma_1 - \sigma_3 = 2c\) is constant, so the deviator stress stays 200 kN/m² (c = 100 kN/m²).

Question 5Easy
What is the primary factor that governs the shear strength of sands?
Full explanation

Answer: D. Friction angle

Sands have c ≈ 0, so τ = σ′ tan φ: their strength depends on the friction angle φ.

Question 6Easy
Under which of the following conditions is an element subjected to stresses said to be in a state of triaxial stress?
Full explanation

Answer: B. When principal stresses act along three mutually perpendicular directions

Triaxial stress means non-zero principal stresses in all three mutually perpendicular directions.

Question 7Medium
A sample of soil failed in a triaxial test under a deviator stress of 200 kN/m² when the confining pressure was 100 kN/m². For the sample, if the confining pressure had been 200 kN/m², what would have been the deviator stress at failure? Assume c = 0.
Full explanation

Answer: A. 400 kN/m²

c = 0 ⇒ \(\sigma_1/\sigma_3 = \tan^2(45^\circ+\phi/2)\) is constant = 300/100 = 3 (φ = 30°). With σ₃ = 200, σ₁ = 600, so σd = 400 kN/m².

Question 8Easy
Identify the instrument used for finding the shear strength of soil that consists of a loading frame operated by a hand screw, a proving ring with a dial, a deformation dial gauge and conical seatings holding a cylindrical soil specimen without any surrounding cell.
Full explanation

Answer: A. Unconfined compression test apparatus

A cylindrical specimen between conical seatings, loaded by a hand-operated frame with a proving ring and dial gauge and with no confining cell, is the unconfined compression test apparatus.

Question 9Easy
If the cohesion value of soil is zero, the Mohr envelope will pass through:
Full explanation

Answer: B. the origin

τ = c + σ tan φ with c = 0 gives τ = σ tan φ: a straight line through the origin.

Question 10Easy
If the normal and shear stresses corresponding to failure are plotted, then a curve is obtained. The plot or curve is called the ______.
Full explanation

Answer: C. strength envelope

The curve of (σ, τ) at failure, tangent to all the Mohr circles at failure, is the strength (failure) envelope.

Question 11Easy
Shear resistance of soil can be attributed to:
Full explanation

Answer: C. cohesion and friction

τ = c + σ tan φ: shear resistance comes from cohesion and from internal friction (with interlocking).

Question 12Easy
______ is a method of measuring the undrained shear strength of a cohesive soil.
Full explanation

Answer: A. Vane shear test

The vane shear test measures the undrained shear strength of soft cohesive soils directly, in the lab or in the field.

Question 13Medium
According to the Mohr–Coulomb theory of failure, useful in case of soils, which of the following statements is INCORRECT?
Full explanation

Answer: C. The failure criterion depends on the intermediate principal stress

Mohr–Coulomb uses only σ₁ and σ₃; the intermediate principal stress σ₂ has no influence. So (c) is incorrect.

Question 14Medium
In a direct shear test, the soil is subjected to more stress at the ______.
Full explanation

Answer: D. edges

Stress in a direct shear box is non-uniform: it concentrates at the edges of the specimen and is lower at the centre.

Question 15Easy
The failure plane in a direct shear test is the ______.
Full explanation

Answer: A. horizontal plane

The two halves of the box slide past each other, forcing failure along the horizontal plane between them.