Numerical (Water)

Two plates are placed at a distance of 0.15 mm apart. The lower plate is fixed while the upper plate having surface area 1.0 m² is pulled at 0.3 m/s. Find the force and power required to maintain this speed, if the fluid separating them is having viscosity 1.5 poise.

Force and Power for Moving Plate Problem Statement Two plates are placed at a distance of 0.15 mm apart. The […]

Two plates are placed at a distance of 0.15 mm apart. The lower plate is fixed while the upper plate having surface area 1.0 m² is pulled at 0.3 m/s. Find the force and power required to maintain this speed, if the fluid separating them is having viscosity 1.5 poise. Read More »

Determine the intensity of shear of an oil having viscosity = 1.2 poise and is used for lubrication in the clearance between a 10 cm diameter shaft and its journal bearing. The clearance is 1.0 mm and the shaft rotates at 200 r.p.m.

Shear Stress in a Journal Bearing Problem Statement Determine the intensity of shear of an oil having viscosity = 1.2

Determine the intensity of shear of an oil having viscosity = 1.2 poise and is used for lubrication in the clearance between a 10 cm diameter shaft and its journal bearing. The clearance is 1.0 mm and the shaft rotates at 200 r.p.m. Read More »

A plate 0.025 mm distant from a fixed plate, moves at 50 cm/s and requires a force of 1.471 N/m² to maintain this speed. Determine the fluid viscosity between the plates in poise.

Fluid Viscosity Calculation Problem Statement A plate 0.025 mm distant from a fixed plate, moves at 50 cm/s and requires

A plate 0.025 mm distant from a fixed plate, moves at 50 cm/s and requires a force of 1.471 N/m² to maintain this speed. Determine the fluid viscosity between the plates in poise. Read More »

The velocity distribution for flow over a flat plate is given by u = 3/2 y – y^(3/2) , where u is the point velocity in metre per second at a distance y metre above the plate. Determine the shear stress at y = 9 cm. Assume dynamic viscosity as 8 poise.

Shear Stress on a Flat Plate Calculation Problem Statement The velocity distribution for flow over a flat plate is given

The velocity distribution for flow over a flat plate is given by u = 3/2 y – y^(3/2) , where u is the point velocity in metre per second at a distance y metre above the plate. Determine the shear stress at y = 9 cm. Assume dynamic viscosity as 8 poise. Read More »

Find the minimum size of a glass tube that can be used to measure a water level if the capillary rise in the tube is to be restricted to 2 mm. Consider the surface tension of water in contact with air as 0.073575 N/m.

Minimum Tube Size for Capillary Rise Problem Statement Find the minimum size of a glass tube that can be used

Find the minimum size of a glass tube that can be used to measure a water level if the capillary rise in the tube is to be restricted to 2 mm. Consider the surface tension of water in contact with air as 0.073575 N/m. Read More »

An oil of viscosity 5 poise is used for lubrication between a shaft and sleeve. The diameter of the shaft is 0.5 m and it rotates at 200 r.p.m. Calculate the power lost in oil for a sleeve length of 100 mm. The thickness of the oil film is 1.0 mm.

Power Loss in Lubrication Calculation Problem Statement An oil of viscosity 5 poise is used for lubrication between a shaft

An oil of viscosity 5 poise is used for lubrication between a shaft and sleeve. The diameter of the shaft is 0.5 m and it rotates at 200 r.p.m. Calculate the power lost in oil for a sleeve length of 100 mm. The thickness of the oil film is 1.0 mm. Read More »

The capillary rise in a glass tube is not to exceed 0.2 mm of water. Determine its minimum size (diameter), given that the surface tension for water in contact with air is 0.0725 N/m.

Minimum Tube Size for Capillary Rise Problem Statement The capillary rise in a glass tube is not to exceed 0.2

The capillary rise in a glass tube is not to exceed 0.2 mm of water. Determine its minimum size (diameter), given that the surface tension for water in contact with air is 0.0725 N/m. Read More »

Calculate the capillary effect in millimetres in a glass tube of 4 mm diameter, when immersed in (i) water, and (ii) mercury. The temperature of the liquid is 20°C and the values of the surface tension of water and mercury at 20°C in contact with air are 0.073575 N/m and 0.51 N/m respectively. The angle of contact for water is zero and that for mercury is 130°. Take density of water at 20°C as equal to 998 kg/m³.

Capillary Effect Calculation Problem Statement Calculate the capillary effect in millimetres in a glass tube of 4 mm diameter, when

Calculate the capillary effect in millimetres in a glass tube of 4 mm diameter, when immersed in (i) water, and (ii) mercury. The temperature of the liquid is 20°C and the values of the surface tension of water and mercury at 20°C in contact with air are 0.073575 N/m and 0.51 N/m respectively. The angle of contact for water is zero and that for mercury is 130°. Take density of water at 20°C as equal to 998 kg/m³. Read More »

The pressure outside a water droplet of diameter 0.04 mm is 10.32 N/cm² (atmospheric pressure). Calculate the pressure within the droplet if the surface tension of water is 0.0725 N/m.

Pressure Inside a Water Droplet Problem Statement The pressure outside a water droplet of diameter 0.04 mm is 10.32 N/cm²

The pressure outside a water droplet of diameter 0.04 mm is 10.32 N/cm² (atmospheric pressure). Calculate the pressure within the droplet if the surface tension of water is 0.0725 N/m. Read More »

The surface tension of water in contact with air at 20°C is 0.0725 N/m. The pressure inside a droplet of water is to be 0.02 N/cm² greater than the outside pressure. Calculate the diameter of the droplet of water.

Droplet Diameter from Surface Tension Problem Statement The surface tension of water in contact with air at 20°C is 0.0725

The surface tension of water in contact with air at 20°C is 0.0725 N/m. The pressure inside a droplet of water is to be 0.02 N/cm² greater than the outside pressure. Calculate the diameter of the droplet of water. Read More »

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