Discharge Over a Broad-Crested Weir
Problem Statement
A broad-crested weir of length 40 m has a head of water 400 mm above its crest.
Find the maximum discharge neglecting velocity of approach. If velocity of approach is considered,
find the maximum discharge when the channel has a cross-sectional area of 40 m² on the upstream side.
Take Cd = 0.6.
Given Data
| Length of Weir (L) | 40 m |
| Head of Water (H) | 0.4 m |
| Coefficient of Discharge (Cd) | 0.6 |
| Cross-Sectional Area of Channel (A) | 40 m² |
| Acceleration due to Gravity (g) | 9.81 m/s² |
1. Maximum Discharge Without Velocity of Approach
The maximum discharge over a broad-crested weir without considering velocity of approach is given by:
Qmax = 1.705 Cd L H3/2Substituting values:
Qmax = 1.705 × 0.6 × 40 × (0.4)3/2Calculation gives:
Qmax ≈ 10.352 m³/s2. Velocity of Approach
Velocity of approach is given by:
Va = Qmax / A = 10.35 / 40 = 0.25875 m/sVelocity head is calculated as:
ha = Va2 / (2g) = (0.25875)2 / (2 × 9.81) = 0.0034 m3. Maximum Discharge Considering Velocity of Approach
The corrected discharge equation is:
Qmax = 1.705 Cd L [(H + ha)3/2 - ha3/2]Substituting values:
Qmax = 1.705 × 0.6 × 40 × [(0.4 + 0.0034)3/2 - (0.0034)3/2]Calculation gives:
Qmax ≈ 10.476 m³/sConclusion
The maximum discharge over the broad-crested weir without velocity of approach is 10.352 m³/s.
Considering velocity of approach, the corrected discharge is 10.476 m³/s.