15 questions. Tap an option to check it instantly, then read the solution.
Practice SSC JE and other civil engineering exam questions on beams and plane trusses: truss assumptions, perfect, deficient and redundant trusses (m = 2j − 3), simple, compound and complex trusses, zero-force members, the method of joints, the method of sections, and how trusses differ from beams and frames. Tap an option to check it, then open the full explanation for each question.
Question 1Medium
In a triangular truss ABC with span AC = 6 m, pin at A, roller at C and a 10 kN downward load at B, find the force in member AB. (Take ∠BAC = 60° and ∠BCA = 30°.)
At B the members AB and BC are at right angles. Resolving along each: FAB = 10 cos 30° = 5√3 kN, FBC = 10 sin 30° = 5 kN, both compressive.
Question 2Medium
In the cantilever truss shown (top chord A–B–C attached to a wall at A, vertical BD, members AD, ED and CD, with CD inclined at 30° at C, and 100 t load at B), the force in member BD is:
A beam carries loads acting across (perpendicular to) its axis, which cause bending and shear.
Question 11Medium
In the two-bay truss shown (bottom chord A–C–B with pin at A and roller at B; top chord D–E–F; 4 t horizontal load at D and 5 t vertical load at E), the force in member BC is:
Truss members are pin-jointed and loaded at joints, so they carry only axial force; frame members are rigidly jointed and carry bending.
Question 13Hard
Which of the following statements is true? A. If a truss has a non-triangular element, it will essentially be unstable. B. In such cases instability is the most probable result, but there are exceptions.
A non-triangular panel usually makes a truss unstable, but not always — other members can still make the whole truss rigid. So B is true, A (‘essentially’) is too strong.
Question 14Hard
In the truss shown (bottom chord A–C–E with AC = CE = 4 m, top chord B–D, end members inclined at 60°, pin at A, roller at E; loads 10 t at B and 5 t at D), the force in member AC is:
RA = 8.75 t. At A: FAB sin 60° = 8.75 → AB compressive; then FAC = FAB cos 60° = 8.75/√3 t tensile.
Question 15Medium
In the symmetrical truss shown (bottom chord A–C–B, apex D, vertical CD, base angle 30°, pin at A, roller at B, 3 t load at D), the force in member BC is: