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Stress and Strain MCQs – Part 1

15 questions. Tap an option to check it instantly, then read the solution.

Practice SSC JE and other civil engineering exam questions on stress and strain: Hooke's law, Young's modulus, modulus of rigidity, bulk modulus, Poisson's ratio and the relations between elastic constants, volumetric strain, the stress–strain curve of mild steel, composite bars, thermal stress, strain energy and suddenly applied loads. Tap an option to check it, then open the full explanation for each question.

Question 1Medium
A material has linear strains of 0.05, 0.10 and 0.10 along the X, Y and Z directions. The hydrostatic stress at the point is 25 N/mm². Calculate the bulk modulus.
Full explanation

Answer: B. 100 N/mm²

εv = 0.05 + 0.10 + 0.10 = 0.25; K = p/εv = 25/0.25 = 100 N/mm².

Question 2Medium
Linear strains along X, Y and Z in a homogeneous object are 0.05, 0.10 and 0.10. The object measured 20 cm × 10 cm × 10 cm before deformation. Find the volumetric strain and the change in volume.
Full explanation

Answer: A. Volumetric strain = 0.25, change in volume = 5 × 10⁵ mm³

εv = 0.25; V = 2000 cm³; ΔV = 0.25 × 2000 = 500 cm³ = 5 × 10⁵ mm³.

Question 3Easy
Calculate the bulk modulus of an alloy whose modulus of elasticity is 180 GPa and Poisson's ratio is 0.25.
Full explanation

Answer: A. 120 GPa

K = E/[3(1 − 2μ)] = 180/(3 × 0.5) = 120 GPa.

Question 4Easy
What is the meaning of biaxial stress?
Full explanation

Answer: B. Stress acting along two axes

Biaxial = normal stresses along two mutually perpendicular axes (a two-dimensional state of stress).

Question 5Easy
Poisson's ratio for a linear elastic, homogeneous and isotropic material:
Full explanation

Answer: C. remains constant throughout

For such a material Poisson's ratio is a single material constant: the same everywhere, in all directions, and at all stress levels in the elastic range.

Question 6Medium
Which of the following options is INCORRECT?
Full explanation

Answer: C. −(Longitudinal strain ÷ Lateral strain) = Poisson's ratio

Poisson's ratio is −(lateral strain ÷ longitudinal strain); option (c) has it upside down.

Question 7Easy
For an isotropic homogeneous body, the ratio of lateral strain to axial strain is called:
Full explanation

Answer: C. Poisson's ratio

That ratio is Poisson's ratio.

Question 8Medium
If E is the modulus of elasticity, N the modulus of rigidity and K the bulk modulus, which relation is correct?
Full explanation

Answer: A. E = 9NK/(N + 3K)

E = 9KN/(3K + N).

Question 9Easy
Within the elastic limit of a material, the modulus of elasticity is the ratio of:
Full explanation

Answer: C. stress to strain

E = stress ÷ strain.

Question 10Easy
The net area of a round bar resisting tension is the area of cross-section at:
Full explanation

Answer: B. the root of the thread

A threaded bar is weakest where the diameter is smallest — at the root of the thread.

Question 11Medium
If all the dimensions of a prismatic bar are doubled, the maximum stress produced in it under its own weight will:
Full explanation

Answer: B. increase to two times

Maximum self-weight stress = γL (at the top); it depends only on length, so doubling L doubles it.

Question 12Easy
The value of Poisson's ratio of concrete lies approximately in the range:
Full explanation

Answer: C. 0.15 to 0.2

Concrete: μ ≈ 0.15–0.2 (IS 456 uses 0.2).

Question 13Medium
The relation between bulk modulus K, Young's modulus E and Poisson's ratio 1/m is:
Full explanation

Answer: D. K = mE/[3(m − 2)]

E = 3K(1 − 2/m) ⇒ K = mE/[3(m − 2)].

Question 14Medium
The phenomenon of slow extension of a material, increasing with time under a constant load, is called:
Full explanation

Answer: A. Creeping

Slow, time-dependent extension under a constant sustained load is creep. (The book's printed key gives yielding; see the note.)

Question 15Easy
Poisson's ratio of rubber lies between:
Full explanation

Answer: C. 0.45 and 0.50

Rubber is nearly incompressible, so μ ≈ 0.45–0.5.