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Moment MCQs – Part 1

11 questions. Tap an option to check it instantly, then read the solution.

Practice SSC JE and other civil engineering exam questions on moments: moment of a force, moment at a hinge, first and second moment of area, centroids of composite sections, moment of inertia of rectangles, triangles, circles and semicircles, the parallel and perpendicular axis theorems, polar moment of inertia and mass moment of inertia. Tap an option to check it, then open the full explanation for each question.

Question 1Medium
For a semicircular plate of diameter D and radius R, with y as the vertical axis and x as the horizontal axis passing through the diameter, the moment of inertia about the y-axis will be:
Full explanation

Answer: D. πD⁴/128

About its diameter or its axis of symmetry, a semicircle has half the moment of inertia of the full circle: ½ × πD⁴/64 = πD⁴/128.

Question 2Medium
Locate the centroid, measured from the base AB, of a rectangular section 200 mm wide and 300 mm high from which a circle of diameter 150 mm, centred 100 mm below the top edge, has been removed.
Full explanation

Answer: A. 129.1 mm

ȳ = (A₁y₁ − A₂y₂)/(A₁ − A₂) = (60000×150 − 17671×200)/(60000 − 17671) ≈ 129.1 mm.

Question 3Medium
Select the correct statement regarding the first and second moments of area of a circular lamina of radius R.
Full explanation

Answer: C. The first moment of area may be either negative or positive depending on the chosen reference axes, but the second moment of area is always positive.

First moment ∫y dA can be +, − or 0 depending on the axis; second moment ∫y² dA uses squared distances, so it is always positive.

Question 4Medium
The polar moment of inertia of a semicircular lamina of radius R about its central axis (through the centre of the diameter, perpendicular to the plane) is:
Full explanation

Answer: C. πR⁴/4

J = Ix + Iy = πR⁴/8 + πR⁴/8 = πR⁴/4.

Question 5Easy
A semicircular lamina has radius R and diameter D. Determine its moment of inertia about the diametrical axis.
Full explanation

Answer: D. πR⁴/8

I = πD⁴/128 = π(2R)⁴/128 = πR⁴/8.

Question 6Easy
The moment of inertia of a body is a measure of:
Full explanation

Answer: D. its resistance against rotation

Mass moment of inertia measures how hard it is to change a body's rotational motion.

Question 7Easy
Identify the property that changes as a function of the geometrical dimensions of a section in structural materials:
Full explanation

Answer: B. Moment of inertia

Moment of inertia depends only on the size and shape of the section; the others are material properties.

Question 8Easy
The dimension of angular velocity is:
Full explanation

Answer: B. T⁻¹

ω = dθ/dt; angle is dimensionless, so ω has dimension T⁻¹.

Question 9Easy
The moment of inertia of a circular area about its diameter is Ixx. The moment of inertia of the same area about an axis perpendicular to its plane (through the centre) is Izz. Which statement is correct?
Full explanation

Answer: A. Ixx is always less than Izz

Izz = Ixx + Iyy = 2Ixx, so Ixx is always less than (half of) Izz.

Question 10Easy
The moment at a hinge will be:
Full explanation

Answer: B. Zero

A hinge allows free rotation, so it cannot transmit a moment: the bending moment there is zero.

Question 11Easy
The moment of inertia of a triangular section (height h, base b) about its base is:
Full explanation

Answer: C. bh³/12

I about the base = bh³/12 (three times the centroidal value bh³/36).